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AVprozaik [17]
3 years ago
10

A rectangular patio is 9 ft by 6 ft. When the length amd width are increased by the same amount, the area becomes 88 sq ft. Ging

er is using the zero product property to solve the equation (6+x)(9+x)= 88. What do her solutions represent?
Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0
( 6 + x)(9 + x) =88

54 + 15x + x^2 = 88

x^2 + 15x - 34 = 0

(x + 17)(x - 2) = 0
using zero product property:-
x + 17 =  0  or x - 2 = 0    giving:-

x = -17 , x = 2

x is the amount that the length and width are increased by.

x = -17 is negative and doesn't make sense in this context  and can be ignored; so the amount of increase is  2 feet.

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PEMDAS

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5 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 9% each year. If this
frozen [14]

Answer (prediction, first edit):

5,600,000

Equation:

200,000+(18,000*200)=5,600,000

7 0
2 years ago
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A warehouse floor has a perimeter of 6,615 feet what is the perimeter of the floor in yards
worty [1.4K]

Answer:

1xgr7`0ryu932

Step-by-step explanation:

6 0
3 years ago
A cleaner recommends mixing 1½ cup of cleaner for every 12 cups of water. What is the ratio of cleaner to water in simplest form
guapka [62]
We know that

<span>1½ cup of cleaner-------> (1*2+1)/2-----> 3/2 cup of cleaner

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1/8</span>
6 0
3 years ago
The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha
kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

\mu = 3500 \times 0.0004 = 1.4

The probability that 2 or fewer cars will be stolen is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466

P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452

P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

4 0
1 year ago
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