The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.
Answer:
A) 147.6 sq m
Step-by-step explanation:
Separate the pyramided out into 4 triangles and add those
3 of them (sides) will be the same

This is one half of the side, multiply by 2 to get the area of the entire side, 40 square m.
The area of all 3 sides together is 40*3 = 120 sq m
For your base, your height will be 6.9 and your base is 4
A = 13.8 sq m
multiply by 2 again for the entire base
A=27.6 sq m
Now add both
120 + 27.6
1 is B
2 is A.fes.fdsf.ef.sf.esf.esfs.ef