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Zepler [3.9K]
3 years ago
10

How much of an alloy that is 10 percent copper should be mixed with 500 ounces of an alloy that is 90?

Mathematics
1 answer:
ladessa [460]3 years ago
6 0
So 500ounces is 90% of the alloy.
So 500:90
Now divide both sides by 9.
500/9:10
So thats
55.56:10 or
55 5/9:10
Or keep it as
500/9:10
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algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

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collect like terms

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Get RS:

RS = 4x-9

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RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

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