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3 years ago

Make y the subject of the formula

Mathematics

1 answer:

podryga [215]3 years ago

7 0

Answer:

D. $y = \frac{ {x}^{2} - w }{2z}$

Step-by-step explanation:

$w = {x}^{2} - 2yz \\ \\ 2yz = {x}^{2} - w \\ \\ \huge \red{ y = \frac{ {x}^{2} - w }{2z} }$

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4 years ago

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3 years ago

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jasenka [17]

Answer:

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3 years ago

Determine which point is the solution to the given system.

KatRina [158]

Answer:

Step-by-step explanation:

We equate both the y's and solve for x algebraically:

$-\frac{4}{7}x+16=-\frac{2}{7}x+12\\16-12=-\frac{2}{7}x+\frac{4}{7}x\\4=\frac{2}{7}x\\x=\frac{4}{\frac{2}{7}}\\x=14$

Now taking the value x= 14 and putting it in the 1st equation would give us y:

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7 0

4 years ago

Write the six terms of each arithmetic sequencePlease see picture for question

chubhunter [2.5K]

ANSWER

The six terms for the arithmetic sequence is 1.6, 1.2, 0.8. 0.4, 0, -0.4

EXPLANATION

Given that;

$\begin{gathered} a_n\text{ = a}_{n\text{ - 1}}\text{ - 0.4} \\ \text{ a}_1\text{ = 1.6} \end{gathered}$

To find the second term, let n = 2

$\begin{gathered} \text{ a}_2\text{ }=\text{ a}_{2\text{ - 1}}\text{ - 0.4} \\ \text{ a}_2\text{ }=\text{ a}_1\text{ - 0.4} \\ \text{ a}_1\text{ = 1.6} \\ \text{ a}_2\text{ }=\text{ 1.6 - 0.4} \\ \text{ a}_2\text{ }=\text{ 1.2} \end{gathered}$

To find the third term, let n = 3

$\begin{gathered} \text{ a}_3\text{ }=\text{ a}_{3\text{ - 1}}\text{ - 0.4} \\ \text{ a}_3\text{ }=\text{ a}_2\text{ - 0.4} \\ \text{ a}_2\text{ = 1.2} \\ \text{ a3 }=\text{ 1.2 - 0.4} \\ \text{ a}_3\text{ = 0.8} \end{gathered}$

To find the fourth term, let n = 4

$\begin{gathered} \text{ a}_4\text{ }=\text{ a}_{4-\text{ 1}}\text{ - 0.4} \\ \text{ a}_4\text{ = a}_3\text{ - 0.4} \\ \text{ a}_3\text{ = 0.8} \\ \text{ a}_4\text{ = 0.8 - 0.4} \\ \text{ a}_4\text{ = 0.4} \end{gathered}$

To find the fifth term, let n = 5

$\begin{gathered} \text{ a}_5\text{ = a}_{5\text{ - 1}}\text{ - 0.4} \\ \text{ a}_5\text{ }=\text{ a}_4\text{ - 0.4} \\ \text{ a}_4\text{ = 0.4} \\ \text{ a}_5\text{ = 0.4 - 0.4} \\ \text{ a}_5\text{ = 0} \end{gathered}$

To find the 6th term, let n = 6

$\begin{gathered} \text{ a}_6\text{ }=\text{ a}_{6\text{ - 1}}\text{ - 0.4} \\ \text{ a}_6\text{ = a}_5\text{ - 0.4} \\ \text{ a}_5\text{ = 0} \\ \text{ a}_6\text{ = 0 - 0.4} \\ \text{ a}_6\text{ = -0.4} \end{gathered}$

Hence, the six terms for the arithmetic sequence is 1.6, 1.2, 0.8. 0.4, 0, -0.4

5 0

1 year ago