Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A
Hello!
The equation for a circle is
(h,k) is the center
r is the radius
Put in the values you know
Simplify
The equation is
Hope this helps!
Answer:
x=10°
y = 12°
Step-by-step explanation:
<TSV = 5x + 4x = 90°
=> 9x = 90°
Divide by 9,
x = 10°
<RSU = 10y + 10° + 5x = 180°
=> 10y + 10° + 5*10° = 180°
=> 10y + 10° + 50° = 180°
=> 10y + 60° = 180°
Subtract 60° on both sides,
10y = 180° - 60° = 120°
Divide by 10,
y = 120° / 10 = 12°
Since it's a Trapezoid with its non - parallel sides equal to one another,
[ By forming co - interior angle pair ]
Now, similarly,
Similarly,
