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AnnZ [28]
3 years ago
14

If Y = 12 inches, Z = 14 inches, H = 5 inches, and W = 4 inches, what is the area of the object?

Mathematics
2 answers:
Alla [95]3 years ago
7 0
126 square inches is the answer
OverLord2011 [107]3 years ago
3 0
126 square inches hope that helps
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a slab or ribs at the butcher costs $4.55 per pound how much will it cost if you buy 3.5 pounds of ribs round to the nearest pen
lozanna [386]
15.93 because 4.55 times 3 and (4.55/2) so you'll end up with 15.93
4 0
3 years ago
Factor tree of the prime factorization of number 280
Sphinxa [80]
The prime factorization number is 280 I got 2.2.5.7
8 0
3 years ago
Read 2 more answers
Evan has 2 pieces of wood: one is 90 inches and the other is 72 inches.he wants to cut both pieces of wood into smaller pieces s
Gre4nikov [31]

72/2=36

90/2=45

2+2=4 pieces of wood

6 0
3 years ago
What is the square root of 88 plus(+) the square root of 95?
Tju [1.3M]
Square root of 88 is 9.38083152
Square root of 95 is 9.746794345
9.38083152 + 9.746794345 = 19.12762586

5 0
3 years ago
Ruby has a bird feeder which is visited by an average of 13 birds every 2 hours during daylight hours. What is the probability t
zalisa [80]

Answer:

62.93%

Step-by-step explanation:

We have to solve it by a Poisson distribution, where:

p (x = n) = e ^ (- l) * l ^ (x) / x!

Where he would come being the number of birds that there would be in 40 minutes, we know that in 2 hours, that is 120 minutes there are 13, therefore in 40 there would be:

l = 13 * 40/120

l = 4,333

Now, we have p (x> 3) and that is equal to:

p (x> 3) = 1 - p (x <= 3)

So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

p (x = 1) = 2.72 ^ (- 4.33) * 4.33 ^ (1) / 1! = 0.0568

p (x = 2) = 2.72 ^ (- 4.33) * 4.33 ^ (2) / 2! = 0.12310

p (x = 3) = 2.72 ^ (- 4.33) * 4.33 ^ (3) / 3! = 0.17767

If we add each one:

0.01313 + 0.0568 + 0.12310 + 0.17767 = 0.3707

replacing:

p (x> 3) = 1 - 0.3707

p (x> 3) = 0.6293

Which means that the probability is 62.93%

5 0
3 years ago
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