Functions cannot have the same X value (the first number), but they can have the same Y value (the second number).
<span>A. {(1,2),(2,3),(3,4),(2,1),(1,0)}
B. {(2,−8),(6,4),(−3,9),(2,0),(−5,3)}
C. {(1,−3),(1,−1),(1,1),(1,3),(1,5)}
D. {(−2,5),(7,5),(−4,0),(3,1),(0,−6)}
Choice A. has two repeating X values [(1,2) and (1,0), (2,3) and (2,1)]
Choice B. has one repeating X value [(2, -8) and (2,0)]
Choice C. all has a repeating X value (1)
Choice D doesn't have any repeating X values.
In short, your answer would be choice D [</span><span>{(−2,5),(7,5),(−4,0),(3,1),(0,−6)}] because it does not have any repeating X values.</span>
Answer:
it's x= 1±sqrt(47)
Step-by-step explanation:
Answer:
87.5%
Step-by-step explanation:
Complete question -
75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?
Solution
Given
People who order fish at the Doug's Diner = 75%
Out of this 75%, 90% also order fries which means that nearly 67.5% ordered fries with the fish.
Given that, 80% of people dining at Doug's Diner order fries
Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%
The probability of customers who ordered fish = 100 - 12.5% = 87.5%
Can you take a better picture please
