Can someone help me before 4:00 pls

serg [7]

The answer is C. Why? Well, see below!

A would be incorrect because the problem is asking what the area of the stamp would be. In order to find area, we multiply length and width by each other. The given equation we initially had shows division, and would therefore be incorrect. B would be incorrect because although the equation has the correct evaluation symbol, the formula for identifying length would be L = A / W, which means length equals area divided by width. Because the area is 1/4 in this problem, the expression used for evaluation would be 1/4 divided by 1/5. D is incorrect because, like B, the evaluation expression would be 1/4 divided by 1/5.

Your final answer: Because C is the only problem that gives us a corresponding expression to the initial expression, C is the correct answer. If you need extra help, let me know and I will gladly assist you.

7 0

2 years ago

Read 2 more answers

Which net represents this solid figure? (The first picture is the solid figure the rest are the choices

tatyana61 [14]

The solid figure is represented by the second option.

Step-by-step explanation:

The solid figure in the question is a cuboid.
On opening, it will have 6 faces, each of which will be a rectangle.
All the corners or edges will have 90° or right angles.
Also, on opening, one side will have 2 other faces attached to it on top and bottom which is seen in the second figure.

3 0

3 years ago

if the expression (2x^4)^3 was written in ax^b form, which of the following would be the sum of a and b

Liula [17]

Answer:20

Step-by-step explanation:

4 0

3 years ago

In a recent year, the scores for the reading portion of a test were normally distributed, with a mean of 22.4 and a standard dev

Dovator [93]

Using the normal distribution, we have that:

a) The probability of a student scoring less than 19 is 0.2709 = 27.09%.

b) The probability of a student scoring between 17.7 and 27.1 is 0.6424 = 64.24%.

c) The probability of a student scoring more than 33.1 is 0.0179 = 1.79%.

d) The correct option is: B. The event in part (c) is unusual because its probability is less than 0.05.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 22.4, \sigma = 5.1$

Item a:

The probability is the <u>p-value of Z when X = 19</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{19 - 22.4}{5.1}$

Z = -0.67.

Z = -0.67 has a p-value of 0.2709.

The probability of a student scoring less than 19 is 0.2709 = 27.09%.

Item b:

The probability is the <u>p-value of Z when X = 27.1 subtracted by the p-value of Z when X = 17.7</u>, hence:

X = 27.1:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{27.1 - 22.4}{5.1}$

Z = 0.92.

Z = 0.92 has a p-value of 0.8212.

X = 17.7:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17.7 - 22.4}{5.1}$

Z = -0.92.

Z = -0.92 has a p-value of 0.1788.

0.8212 - 0.1788 = 0.6424.

The probability of a student scoring between 17.7 and 27.1 is 0.6424 = 64.24%.

Item c:

The probability is <u>one subtracted by the p-value of Z when X = 33.1</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{33.1 - 22.4}{5.1}$

Z = 2.1.

Z = 2.1 has a p-value of 0.9821.

1 - 0.9821 = 0.0179.

The probability of a student scoring more than 33.1 is 0.0179 = 1.79%.

Item d:

Probabilities less than 0.05 are unusual, hence the correct option is:

B. The event in part (c) is unusual because its probability is less than 0.05.

More can be learned about the normal distribution at brainly.com/question/28135235

#SPJ1

8 0

2 years ago

Find n(A) for the following set.A = the set of integers between - 27 and 27n(A)=

Svetllana [295]

The answer is:

B. the statement is false bacuase 8 is not an element of the set.

The set only has the elemnets 1,2,5,7

4 0

1 year ago