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Naya [18.7K]
3 years ago
6

Can someone help me before 4:00 pls

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

yes

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Decimal equivalent of 143%
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1.43 as a decimal

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%143 = 1.43

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4 years ago
I need to solve this to get zero can you help?
Alex

Given a right triangle with the side lengths of legs = 9 and 13

For the required angle :

opposite side = 9

adjacent side = 13

so,

\begin{gathered} \tan \theta=\frac{opposite}{adjacent}=\frac{9}{13} \\  \\ \theta=\tan ^{-1}\frac{9}{13}=34.7 \end{gathered}

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3 years ago
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Evaluate the cosine if the angle of rotation which contains the point (9, -3) on its terminal side
Liono4ka [1.6K]

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}

6 0
3 years ago
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