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Helga [31]
2 years ago
9

Decimal equivalent of 143%

Mathematics
1 answer:
daser333 [38]2 years ago
7 0

Answer:

1.43 as a decimal

Step-by-step explanation:

%143 = 1.43

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The spinner is divided into a equal sections which two events have the same probability
myrzilka [38]

Answer:

its A

Step-by-step explanation:

7 0
3 years ago
I need help with this practice I am having a tough time solving it properly
Monica [59]

Given:

There are given that the parent functions as a cosine function:

Where,

The amplitude of the function is 9.

The vertical shift is 11 units down.

Explanation:

To find the cosine function, we need to see the standard form of the cosine function:

f(x)=acos(bx+c)+d

Where,

a is the amplitude of the function,

Now,

According to the question:

The amplitude of the function is 9, which means:

f(x)=9cos(bx+c)+d

The vertical shift is 11 units down, which means:

f(x)=9cos(bx+c)-11

For period:

\begin{gathered} f(x)=-9cos(\frac{12\pi}{7}x+0)-11 \\ f(x)=-9cos(\frac{12\pi}{7}x)-11 \end{gathered}

Final answer:

Hence, the cosine function is shown below;

f(x)=-9cos(\frac{12\pi}{7}x)-11

4 0
1 year ago
The histogram shows the numbers of people who volunteered for community service and the number of hours they worked. Use the his
Nadusha1986 [10]
It would be C.60 If you add the column of  16-20 and 21-25 it makes 60.
8 0
3 years ago
Read 2 more answers
Can anybody help me?
Sloan [31]

Answer:

7⅓

Step-by-step explanation:

2 ÷ 3⁄11 → 2 × 3⅔ >> 7⅓

Dividing by a fraction is the exact same as multiplying by its multiplicative inverse.

* 3⅔ = 11⁄3

* 7⅓ = 22⁄3

I am joyous to assist you anytime.

6 0
3 years ago
In a sample of 70 stores of a certain​ company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi
uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

n = 70, p = \frac{62}{70} = 0.886

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95​% confidence using the​ large-sample method.

We need at least n stores.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.886*0.114}

\sqrt{n} = \frac{1.96\sqrt{0.886*0.114}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.886*0.114}}{0.04})^{2}

n = 242.5

Rounding up

We need at least 243 stores.

5 0
2 years ago
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