Decimal equivalent of 143%

Recall that two angles are complementary if the sum of their measures is 90 degrees°. find the measures of two complementary ang

Julli [10]

Let x represent the smaller angle. Then the larger one is 20+4x. Since they are complementary, their sum is 90. (All measures are degrees.)

90 = x + (20+4x)
90 = 5x +20
70 = 5x
14 = x

The smaller angle is 14°.
The larger angle is 76°.

8 0

3 years ago

What is the value of -33 over 9+2

Nataly [62]

Answer:

11

Step-by-step explanation:

9

+ 2

11

1 2 3 4 5 6 7 8 9 10 11

what the- to easy bro

7 0

2 years ago

What is the equation 5(-6m+7)

steposvetlana [31]

The correct answer to your question is −

-30 m + 35

Hope this helps!

BTW can I have brainliest?

6 0

2 years ago

Read 2 more answers

Emily gives her bird 1/8 cup of bird seeds along with 1/3 cup of grains each day. How much food is given each day to the bird

ANEK [815]

Answer:

11/24 cup

Step-by-step explanation:

What you would do is add 1/8 plus 1/3. To add two fractions, each much have the same denominator. In this case, you would need to multiply 1/8 into 3/24 by multiplying 1/8 by 3 on the denominator and numerator. For 1/3, multiply each the numerator and denominator by 8 getting the fraction 8/24. Now you can line up each fraction and add the numerators, keeping the denominator at 24. That answer would be 11/24. This cannot be simplified, so the answer is 11/24 cup of food.

Whenever you are confused with assignments, it is best to tell your parent to help you or teacher the next day. Hope this helps though!

6 0

2 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago