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2 years ago

12

Kimi’s dog gives birth to a litter of 4 puppies per year, on average. The relationship between time and the expected total numbe

r of puppies is shown on the graph. Which other ordered pairs would fall on this line? Select all that apply.
(0, 0)
(2, 6)
(3, 12)
(4, 14)

2 answers:

Daniel [21]2 years ago

4 0

Answer:

answer is (0, 0) & (3, 12)

Step-by-step explanation:

taking the text right now

denis-greek [22]2 years ago

3 0

Answer:a,c

Step-by-step explanation:

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12/3=4
4 divided by 17/18 equals to 4* 18/17=72/17= 4 4/17
Thus the answer is 4 4/17

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Answer:

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Step-by-step explanation:

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What is the formula to find the circumference of a circle and how do i do it?

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2 years ago

Given the following formula, solve for I.<br> P =<br> 2(1 + b)

patriot [66]

Answer: $l=\dfrac{P}{2}-b$

<u>Step-by-step explanation:</u>

P = 2(l + b)

Divide both sides by 2:

$\dfrac{P}{2}=l+b$

Subtract b from both sides:

$\dfrac{P}{2}-b=l$

<em>Note: You can also multiply b by </em> $\frac{2}{2}$ <em> if you want the left side to be one fraction.</em>

$\dfrac{P}{2}-\bigg(\dfrac{2}{2}\bigg)b=l\\\\\\\dfrac{P-2b}{2}=l$

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2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

Vlad [161]

Answer

$P(A) = 0.30$

$P(B) = 0.77$

$P(A\ n\ B) = 0.22$

$P(A\ u\ B) = 0.85$

Explanation:

Given

See attachment for proper data presentation

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

$Yes = 22$ and $No = 8$

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

$P(A) = 0.30$

Solving (b): P(B)

We only consider data in the Yes column.

Here:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

$P(B) = 0.77$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ n\ B) = 0.22$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

$P(A\ u\ B) = 0.85$

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2 years ago