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3 years ago

Somebody help plz I need some help

Mathematics

1 answer:

Akimi4 [234]3 years ago

3 0

Answer:

Step-by-step explanation:

2x + (x - 9) = 90

(I guessed and checked. It's multiple choice so, why not?)

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Find the sum of 567.20, 890 & 12.901

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Answer:

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3 years ago

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the rocket car was already going 190 mph when the timer started his watch how fast is mph was the rocket car going seven minutes

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Answer:

Daddy

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3 years ago

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The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte

malfutka [58]

1. The area of the rhombus can be found by the formula

$A=\dfrac{d_1\cdot d_2}{2},$ where $d_1,\ d_2$ are rhombus's diagonals.

Note that $d_1=4.5\ dm=45\ cm,$ then

$540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.$

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

$\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.$

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

$\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.$

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

$\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.$

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

$(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.$

Then

$h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.$

Answer: $h=\dfrac{180}{17}\ cm.$

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3 years ago

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What is the equation of the line described below written in slope-intercept form? the line passing through point (2, 4), paralle

WARRIOR [948]

If it helps, y = x can be written as y = 1x + 0.....here ur slope is 1. A parallel line will have the same slope

y = mx + b
slope(m) = 1
(2,4)...x = 2 and y = 4
now we sub and find b, the y int
4 = 1(2) + b
4 = 2 + b
4 - 2 = b
2 = b

so ur parallel equation is : y = x + 2

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4 years ago

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Write an equation for the table in the slope intercept form.

LiRa [457]

Answer:

C. y=1.6x-5

Explanation:

-5-(-8.2)= 1.6

1.6=m

-8.2=1.6(-2)=b

1.6(-2)=-3.2

-8.2-(-3.2)=-5

-5=b

hope this helps =3

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3 years ago