In creating code in JavaScript to run calculations on extremely small numbers, MIN_VALUE as validation in the program can be use to check the lowest value JavaScript can handle
Number.MIN_VALUE returns the smallest positive numeric value representable in JavaScript. It is the number more closer to zero. The value is approximately 5e⁻³²⁴.
Using Number.MIN_VALUE, the value can be printed as follows:
val = Number.MIN_VALUE;
console.log(val); // 5e-324
Therefore, In creating code in JavaScript to run calculations on extremely small numbers, MIN_VALUE as validation in the program can be use to check the lowest value JavaScript can handle.
learn more on JavaScript here: brainly.com/question/13041378?referrer=searchResults
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This is a tough question. I’m not sure if I’ll get it right but I’ll try.
Data structures used for file directories typically have a hierarchical tree structure, referred to as a directory structure. The tree has a root directory, and every file in that system has a unique path.
The simplest method of implementing a directory is to use a linear list of file names with pointers to the data blocks. But another way that you can format a file directory is by using a hash table. With this method, the linear list stores the directory entries, but a hash data structure is also used. The hash table takes a value computed from the file name and return the pointer to the file name any linear list.
So I think it’s C. But I’m not 100% sure.
I hope that helps.
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
