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natka813 [3]
3 years ago
5

Nicky is considering two different companies for textbook rentals. For

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

if youre answer has to be a whole number it would be 3 otherwise it would be  x<4 ( so anything less than 4 )

Step-by-step explanation:

so because we are trying to find which company is less, we need to set up in inequality.

so first lets do company A

because 15 is our reoccuring fee, its going to be the coeifficient

so the equation would be

A - 15x + 20

now lets do company B

because it only 20 every month we dont need to have a constant which means the equation for B would be

B - 20x

so lets put it all together

15x + 20 > 20x ( remember our B side has to be less )

now lets solve it

20 > 5x

we know that if x = 4 then the two would be equal, which means our answer would have to be 3 months.

now always check your work.

15 (3) + 20 = 65

20(3) = 60

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f(x)= 2x -4

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WhIich of the following mathematical expressions is equivalent to the verbal expression "A number, x, squared is 39 more than th
MrRa [10]

Answer:

E. x^2 = 39 + 10x

Step-by-step explanation:

It helps to do one piece of the sentence at a time.

"A number, x, squared is 39 more than the product of 10 and x"

x

"A number, x, squared is 39 more than the product of 10 and x"

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"A number, x, squared is 39 more than the product of 10 and x"

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If BC = 61 and AB = 82, what is the length of AC?
Nitella [24]

Answer:

54.8

Step-by-step explanation:

Pythagorean theorem is a^2+b^2=c^2.

Plug the given values in to get 61^2+b^2=82^2

61^2 is 3,721 and 82^2 is 6,724.

6,724-3,721 is 3,003.

The square root of 3,003, rounded to a reasonable value, is 54.8.

The length of AC is 54.8.

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8 people are boarding a plane 2 have tickets for first class and board before everyone. In how many ways can these people board
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3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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