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3 years ago

Using the following expression written in perfect square form , answer the questions below (x-4)^2=3

Mathematics

1 answer:

Studentka2010 [4]3 years ago

5 0

Answer:

fasholy yo yo dog

Step-by-step explanation:

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What is that simplest form of 9*5/6?

Arturiano [62]

Answer:

7 1/2

Before simplification: 15/2

Step-by-step explanation:

6 0

3 years ago

A calculus exam has a mean of µ = 73 and a standard deviation of σ = 4. Trina's score on the exam was 79, giving her a z-score o

kirza4 [7]

Answer:

I get z = +1.8

x= 79

m= 73;s= 4;z= (x-m)/s= 1.5

hope it helps you

7 0

4 years ago

A patio has an area of 1420 square feet. If the length is 45 1/2, what is the width

Anni [7]

[ Answer ]

$\boxed{Width \ = \ 31\frac{19}{91} \ Ft^{2}}$

[ Explanation ]

Area = 1420

Width = $45\frac{1}{2}$

Area For Rectangle: Length · Width

Use division to find width:

1420 ÷ $45\frac{1}{2}$

Convert mixed numbers to fractions:

1420 = $\frac{1420}{1}$

$45\frac{1}{2}$ = $\frac{91}{2}$

$\frac{1420}{1}$ ÷ $\frac{91}{2}$

Use mixed multiplication:

$\frac{1420*2}{1*91}$

= $\frac{2140}{91}$

Simplify:

= $31\frac{19}{91}$

$\boxed{[ \ Eclipsed \ ]}$

7 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Find the mssing value.<br> I = ? , P = $250.00, r = 4%, t = 2 years

Ber [7]

Answer:

20 I think

Step-by-step explanation:

I mean I would say it is 20

4 0

3 years ago