If it is cylindrical, the circumference is the diameter x pi. If it is rectangular, it is the length of the sides added together.
Answer:
The slope of the line perpendicular to the given line is 2/3
Step-by-step explanation:
step 1
Find the slope of the given line
we have
3x+2y=6
isolate the variable y
2y=-3x+6
y=-(3/2)x+3
The slope of the given line is m=-(3/2)
step 2
Find the slope of the line perpendicular to the given line
Remember that
If two lines are perpendicular, their slopes are opposite reciprocal of each other ( the product of their slopes is equal to -1)
so
m1*m2=-1
we have
m1=-3/2
so
m2=2/3
therefore
The slope of the line perpendicular to the given line is 2/3
<span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= </span><span>8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4
= </span>8r^6s^3 – 9r^5s^4 + 4r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6
= 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6
Hope it helps
The Pythagorean theorem tells you that for legs a and b, and hypotenuse c this relationship holds:
c² = a² + b²
It can be useful to make a couple of rearrangements of this relation.
c = √(a² +b²)
a = √(c² -b²)
1. c = √(10² + 8²) = √164 = 2√41
2. a = √(26² - 10²) = √576 = 24
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It doesn't matter which leg you call "a" and which one you call "b", unless they are specifically marked on the triangle. Then use the marks you are given.
The graphs are attached. Each graph is transformed by a horizontal translation or vertical translation or a reflection.
