Answer:
pi
Step-by-step explanation:
A. - 7x² + 7x + 1 + 8 = 0
- 7x² + 7x + 9 = 0
x = - b ± √b² - 4ac / 2a
= - 7 ± √7² - 4 (-7) (9) / 2 (-7)
= - 7 ± √49 + 252 / - 14
= - 7 ± √ 301 / - 14
x = - 7 + 17.349 / - 14 x = - 7 - 17.349 / - 14
= 10.349 / - 14 = - 24.349 / - 14
= - 0.739 = - 1.739
B. 8x² - 5x² + 6x + 1 = 0
3x² + 6x + 1 = 0
x = - b ± √b² - 4ac / 2a
= - (-5) ± √-5² - 4 (3) (1) / 2 (3)
= 5 ± √25 - 12 / 6
= 5 ± √ 13 / 6
x = 5 + 3.606 /6 x = - 5 - 3.606 / 6
= 8.606/6 = - 8.606/6
= 1.434. = - 1.434
please re-check the answers hope this helps
Answer:
1 to 3
Step-by-step explanation:
For every goal team A scored, team B scored 3 goals.
So when team A scores 1 goal,
Team B scores 3 goals.
1 goal, 3 goals
1:3, or 1 to 3
First, we should answer two simple questions.
1. How many ways can we travel from a-b?
2. How many ways can we travel from b-c?
This is given in the problem - because there are 7 roads connecting a to b, there are 7 ways to get from a-b. Because there are 6 roads from b-c, there are 6 ways to get from b-c.
Now that we understand this, we can use some logic to figure out the rest of the problem. Let's think about each case.
Let's go from a-b. We'll choose road 1 of 7. Now that we are in b, we have 6 more choices. This means that there are 6 ways to get to from a-c if we take road 1 when we go to b.
If we take any road going from a-b, there will be 6 options to get from b-c.
So, we can just add up the number of options because we know that there are 6 routes per road from a-b. This is simply 7*6 = 42. So, there are 42 ways to travel from a to c via b.
