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3 years ago

7

In the game of Sudoku, the correct answer is a 3×3 grid where each cell contains a unique single-character number. Find the prob

ability that the number in a certain square is greater than 9.

1 answer:

Mademuasel [1]3 years ago

8 0

Answer:

impossible

Step-by-step explanation:

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Mrs white wants to crochet beach hits and baby afghans for a church fund raising bazaar. she needs 7 hours to make a hat and 4 h

Georgia [21]

She can make 5 hats and 6 afghans in 60 hours and will make $159 and have a good stock of each item or she could make 8 hats and 1 afghan in 60 hours and make $204 for the most profit.

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3 years ago

Daniels tennis racket is the same length as 21- foot rulers How many inches long is Daniels racket?

vlabodo [156]

Answer:

21

Step-by-step explanation:

5 0

3 years ago

Identify two additional values for x and y in a direct variation relationship where y =11 when x=18

Ann [662]

In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.

So, you can find multiple values that meet this:

y = kx => k = y / x = 11 / 18

=> y = (11/18)x

Now you can give any value to x and fint the value of x that satisfy the relationship:

x           y = (11/18)x

1           11/18

2           11/18 * 2 = 11/9

18          11/18 * 18 = 11

36           11/18 * 36 = 22

So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x

3 0

3 years ago

Iron deficiency anemia is an important nutritional health problem in the U.S. A dietary assessment was performed on 51 boys 9-11

Bond [772]

Answer:

a) Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

b) $t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

c) $12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

Step-by-step explanation:

Information given

$\bar X=12.50$ represent the mean for the daily iron intake

$s=4.75$ represent the sample deviation

$n=51$ sample size

$\mu_o =14.44$ represent the reference value

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Part a

We want to test if the mean iron intake among the low-income group is different from that of the general population, the system of hypothesis would be:

Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

Part b

Since we don't know the population deviation the statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got

$t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

Part c

The confidence interval would be given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

For the 95% confidence interval we can find the critical value in a t distribution with 50 degrees of freedom and we got:

$t_{\alpha/2}= 2.01$

And replacing we got:

$12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

7 0

4 years ago

What is the measurement for MKL?

Lena [83]

Answer:

36 degreees

Step-by-step explanation:

JKL = 9x + 18

54 = 9x + 18

36 = 9x

4 = x

6(4) + 12 = 36

7 0

3 years ago