Answer: could you make the question a little clearer
Step-by-step explanation:
Let x be 1, y=-12
let x be 2, y=-36
let x be 0, y=-4
let x be 3, y =-108
let x be -1, y=-4/3
let x be -2,y=-4/9
Answer:
= 1/x^2
Step-by-step explanation:
Possible derivation:
d/dx(-16 - 1/x + y)
Differentiate the sum term by term and factor out constants:
= d/dx(-16) - d/dx(1/x) + d/dx(y)
The derivative of -16 is zero:
= -(d/dx(1/x)) + d/dx(y) + 0
Simplify the expression:
= -(d/dx(1/x)) + d/dx(y)
Use the power rule, d/dx(x^n) = n x^(n - 1), where n = -1.
d/dx(1/x) = d/dx(x^(-1)) = -x^(-2):
= d/dx(y) - -1/x^2
Simplify the expression:
= 1/x^2 + d/dx(y)
The derivative of y is zero:
= 1/x^2 + 0
Simplify the expression:
Answer: = 1/x^2
Answer:
The parent function of absolute value is
y = |x| .
Step-by-step explanation: