Answer:
B
Step-by-step explanation:
B
x - 4 squared provides 2 real zeros that are the same. These two are not distinct.
The other two come from x^2 - 7x + 10 which has a discriminate of
sqrt(7^2 - 4*1*10) = sqrt(9) = +/- 3 leading to something real and different.
Answer:
NOT PROPORTIONAL
Step-by-step explanation:
The given two fractions are:
and
.
Proportional fractions are those which have the same value when to reduced to the simplest form.
Consider two fractions
and
.
We say they are proportional if
.
Or, if
then we can say the fractions are proportional.
Here the fractions are:
and
.
LHS: 5 X 10 = 50.
RHS: 8 X 8 = 64.
Clearly they are not equal. So, we can say these two fractions are not proportional.
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.

The probability is 1/57.