A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
Answer:
what are the answer choicesss
Step-by-step explanation:
Answer:
<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>
Step-by-step explanation:
6y - 5z = -8 .......... Equation 1
3z = -6 ................... Equation 2
4x - 3y - 2z= 21...... Equation 3
<u>First solve for z in Equation 2</u>
That's
3z = - 6
Divide both sides by 3
<h3>z = - 2</h3>
Next substitute the value of z into Equation 1 in order to find y
We have
6y - 5(-2) = - 8
6y + 10 = - 8
6y = - 8 - 10
6y = - 18
Divide both sides by 6
<h3>y = - 3</h3>
Finally substitute the values of y and z into Equation 3 to find the value of x
That's
4x - 3(-3) - 2(-2) = 21
4x + 9 + 4 = 21
4x + 13 = 21
4x = 21 - 13
4x = 8
Divide both sides by 4
<h3>x = 2</h3>
So the solutions are
<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>
Hope this helps you
The Pythagorean theorem applies to the sides of this right triangle.
... x² + (4/7)² = (5/7)²
... x² = 25/49 -16/49
... x = √(9/49)
... x = 3/7
The unknown side has length 3/7.
_____
You might recognize that this is a 3-4-5 right triangle with a scale factor of 1/7.
