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SOVA2 [1]
3 years ago
15

What is 10% of 3,457?

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

345.7

Step-by-step explanation:

multiply .10 by 3,457 and thqt would be your answer

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What's the answer? 5h(k-13)+3=49-k equality<br><br>please answer...
postnew [5]

Answer: 50k maybe the


Step-by-step explanation:


5 0
3 years ago
Sarah will mix yellow paint and red paint in the ratio 2 parts yellow to 3 parts red to create a certain shade of orange paint.
enyata [817]

Answer:

D. 59.50$

Step-by-step explanation:

Lets make an equation:

we know she is going to use 2 parts of yellow to 3 parts of red and she needs 10 quarts, therefore the equation would be:

2x+3x=10

x = 2

2 * 2 = 4( we need four quarts of yellow paint)

Price for yellow paint = 4 * 5.50 = 22

2 * 3 = 6(we need 6 quarts of red paint)

Price for red paint = 6 * 6.25  37.5

Add those prices: 37.5 + 22 = 59.50$

5 0
3 years ago
You start at (8, 2). You move right 1 unit and down 2 units
vekshin1
(9,0)

X=8+1=9
Y=2-2=0

Hope it helps
6 0
3 years ago
The high temperatures (in degrees Fahrenheit) of a random sample of 5 small towns are: 99.6 99.7 97.9 98.6 97.7 Assume high temp
mylen [45]

Answer: (97.63, 99.77)

Step-by-step explanation:

Given the data:

99.6 99.7 97.9 98.6 97.7

Using calculator, we can obtain the mean and standard deviation of the sample data:

Mean(m) = 98.7

Standard deviation = 0.93

Sample size (n) = 5

Using the relation to find confidence interval :

Mean ± Zcrit * (s/√n)

Zcrit at 99% = 2.576

98.7 ± 2.576 * (0.93 / √5)

Lower limit : 98.7 - (2.576 * 0.4159086) = 97.6286194464 = 97.63 ( 1 decimal place)

Upper limit : 98.7 + (2.576 * 0.4159086) = 99.7713805536 = 99.77 ( 1 decimal place)

(97.6, 99.8)

5 0
3 years ago
Help me with this please
timama [110]

Answer:

\large\boxed{(b)\ \dfrac{x+2}{x-3}}

Step-by-step explanation:

\dfrac{1}{x+1}+\dfrac{x}{x-3}-\dfrac{-x-5}{x^2-2x-3}=(*)\\\\x^2-2x-3=x^2-3x+x-3=x(x-3)+1(x-3)=(x-3)(x+1)\\\\(*)=\dfrac{1(x-3)}{(x+1)(x-3)}+\dfrac{x(x+1)}{(x+1)(x-3)}+\dfrac{-(-x-5)}{(x+1)(x-3)}\\\\=\dfrac{x-3+x^2+x+x+5}{(x+1)(x-3)}=\dfrac{x^2+(x+x+x)+(-3+5)}{(x+1)(x-3)}\\\\=\dfrac{x^2+3x+2}{(x+1)(x-3)}=\dfrac{x^2+2x+x+2}{(x+1)(x-3)}=\dfrac{x(x+2)+1(x+2)}{(x+1)(x-3)}\\\\=\dfrac{(x+2)(x+1)}{(x+1)(x-3)}\qquad\text{cancel (x + 1)}\\\\=\dfrac{x+2}{x-3}

6 0
4 years ago
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