Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d =  -
 -  =
 =  -
 - 
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
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The n th term of an arithmetic sequence is
 =
 =  + (n - 1)d
 + (n - 1)d
 = 2k = 2 × 2 = 4 and
 = 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
 = 4 + (7 × 5) = 4 + 35 = 39
 = 4 + (7 × 5) = 4 + 35 = 39
 
 
        
             
        
        
        
Answer:
I think the answer is C.
Step-by-step explanation:
I hope this helps :)
 
        
             
        
        
        
<h3>
Answer:  6</h3>
Mark the locations -6 and 0 on the number line. Note that going from -6 to 0, or vice versa, will take exactly 6 steps. Put another way, the distance between 0 and -6 is 6 units. Absolute value represents distance, so it is never negative.
We say 
Effectively, all we're doing is removing the negative sign.