You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.
You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.
The ambiguous case is the SAS triangle. This could be easily solved using Law of Sines than Law of Cosines. Take for example: side a = 4, side b = 10, angle A = 23°. Then, we can determine angle B through Sine Law.
sin 23°/4 = sin B/10
B = 77.64°
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(2,8) and (-2 -8) are reflections of each other over both axes
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the scale factor is 4 to 1, or just 4.
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I don't know how to explain this cause i can't like draw on the pic but I'll try my best.
The point G would be at the coordinate (6, 8) (6 on the x-axis and 8 on the y)
The point H is on (7,8)
The point F is on (6,3)
The point E is on (7, 3)
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13Ya is the answers for the question
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