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2 years ago

What is the ratio of new books to used books?

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

6 0

Answer:

7 to 8

Step-by-step explanation:

7-15=8

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Find the missing side lengths leave your answerss as radicals

Sunny_sXe [5.5K]

Answer:

x = 8, y = 4

Step-by-step explanation:

To find x use the sine ratio in the right triangle and the exact value

sin60° = $\frac{\sqrt{3} }{2}$ , thus

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{4\sqrt{3} }{x}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

x × $\sqrt{3}$ = 8 $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

x = 8

--------------------------------------------------------------

To find y use the tangent ratio in the right triangle and the exact value

tan60° = $\sqrt{3}$ , thus

tan60° = $\frac{opposite}{adjacent}$ = $\frac{4\sqrt{3} }{y}$ = $\sqrt{3}$ ( multiply both sides by y )

4 $\sqrt{3}$ = y × $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

y = 4

8 0

2 years ago

What is 1338384.444 x .8

Rom4ik [11]

Answer:

1070707.5552

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

10+11=? aslo sub to my channel Adonday Playz if done ill mark you brainiest

Mariulka [41]

Answer:

your answer is 21, no I meant 69

Step-by-step explanation:

10+11=69

6 0

2 years ago

Read 2 more answers

Help me about this integral

NemiM [27]

The gradient theorem applies here, because we can find a scalar function f for which ∇ f (or the gradient of f ) is equal to the underlying vector field:

$\nabla f(x,y,z)=\langle2xy,x^2-z^2,-2yz\rangle$

We have

$\dfrac{\partial f}{\partial x}=2xy\implies f(x,y,z)=x^2y+g(y,z)$

$\dfrac{\partial f}{\partial y}=x^2-z^2=x^2+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=-z^2\implies g(y,z)=-yz^2+h(z)$

$\dfrac{\partial f}{\partial z}=-2yz=-2yz+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

where C is an arbitrary constant.

So we found

$f(x,y,z)=x^2y-yz^2+C$

and by the gradient theorem,

$\displaystyle\int_{(0,0,0)}^{(1,2,3)}\nabla f\cdot\langle\mathrm dx,\mathrm dy,\mathrm dz\rangle=f(1,2,3)-f(0,0,0)=\boxed{-16}$

5 0

2 years ago

F(x)=2x^2-3x find f(7) (Also can someone help me with the other 2?)

velikii [3]

Answer:

$f(x) = 2 {x}^{2} - 3x \\ f(7) = 2( {7}^{2} ) - 3(7) \\ = 2(49) - 21 \\ = 98 - 21 \\ = 77 \\ g(x) = 4 {x}^{2} + 9x \\ g(3x) = 4(3 {x}^{2} ) + 9(3x) \\ = 4(9 {x}^{2} ) + 27x \\ = 36 {x}^{2} + 27 {x}^{2} \\ = 9x(4x + 3) \\ f(n) = 3 {n}^{2} - 5n + 2 \\ f( - 3) = 3( - {3}^{2} ) - 5( - 3) + 2 \\ = 3(9) + 15 + 2 \\ = 27 + 15 + 2 \\ = 44$

Step-by-step explanation:

Hope that this is helpful.

Have a good day.

6 0

2 years ago