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agasfer [191]
3 years ago
12

True/False: Money that is usable can be easily moved from your home to the store.

Mathematics
2 answers:
egoroff_w [7]3 years ago
4 0

Answer:

true

Step-by-step explanation:

Gekata [30.6K]3 years ago
4 0
True. Money was made meant to be easily accessible wherever you go.
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A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units.
Lelechka [254]

Answer: Second option.

Step-by-step explanation:

You need to use the following formula:

V=\frac{1}{3}Bh

Where "B" is the area of its base and "h" is the height.

According to the data given in the exercise, you know that:

B=7.4 units^2\\\\h=6\ units

Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.

Then, you get:

V=\frac{1}{3}(7.4 units^2)(6\ units)\\\\V=14.8\ units^3

6 0
3 years ago
Read 2 more answers
An equilateral triangle has a perimeter of 48 cm. What is the area?
KiRa [710]

Answer:

A=64\sqrt{3}\ cm^2

Step-by-step explanation:

we know that

An <u><em>equilateral triangle</em></u> has three equal sides and three equal interior angles (each interior angle measure 60 degrees)

so

The perimeter is equal to

P=3b

where

b is the length side of the equilateral triangle

we have

P=48\ cm

substitute

48=3b

solve for b

b=48/3\\b=16\ cm

Find the area

The formula of area applying the law of sines is equal to

A=\frac{1}{2}b^2sin(60^o)

substitute the value of b

A=\frac{1}{2}(16)^2sin(60^o)

sin(60^o)=\frac{\sqrt{3}}{2}

A=\frac{1}{2}(16)^2(\frac{\sqrt{3}}{2})

A=64\sqrt{3}\ cm^2

6 0
3 years ago
NEED HELP ASAP PLEASE WILL GIVE BRAINLYEST
AleksAgata [21]

Answer:

a) 1/2

b) 6/100

c)1/4

I'll explain how I got these answers later.

8 0
3 years ago
Read 2 more answers
Find the value of x²-8y³-36xy-216 when X=2y-6​
Degger [83]

Answer:

4y²+112y+10

Step-by-step explanation:

not rly sure ya :)

3 0
3 years ago
PLEASE HELP ME!!!
Anna007 [38]

Answer:

1)(2x + y \:  \:  \: 2) = (1 \:  \: x - y) \\ so \: compare \: 2x + y = 1...(1) \\ 2 = x - y....(2) \\ 2x + y = 1...(1) \\ x - y = 2....(2) \\ (1) + (2) \\ 3x + 0y = 3 \\ x =  \frac{3}{3}  = 1 ....(3)\\  \\ put \: (3)in \: (1) \\ 2 \times 1 + y = 1 \\ y = 1 - 2 \\ y =  - 1 \\ here \: x = 1 \\ y =  - 1 \\ 2)(x  + 2y \:  \:  \: 3) \: and \: ( - 1 \:  \:  \: 2x - y) \\ here \: x + 2y =  - 1...(1) \\ 2x - y = 3...(2) \\ (2) \times 2 =  > 4x - 2y = 6...(3) \\ x + 2y =  - 1....(1) \\ (1) + (3) \\ 5x + 0y = 5 \\ x =  \frac{5}{5}  = 1....(3) \\ put \: (3) \: in \: (1) \\ 1 + 2y =  - 1 \\ 2y =  - 2 \\ y =  \frac{ - 2}{2}  =  - 1 \\ here \: x = 1 \\ and \:  \\ y =  - 1 \\ thank \: you

5 0
3 years ago
Read 2 more answers
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