Isabella drove 600m.
Mia drove 300 more than Isabella=(600+300)m
=900m.
David drove=8.5km=8500m
Therefore, Distance David drove in meters combined of both distances of Mia and Isabella =[8500-(600+900)]m
=(8500-1500)
=7000 meters or 7 km.
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1/2 turns into 2/4 and 2/4 + 1/4 that equals 3/4 and then 11 plus 6 equals 17 3/4
Answer:
a) F
b) B, E, D
Step-by-step explanation:
a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values
From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2
The gradient of F = (-3units)/(1 unit) = -3
The gradient of A = 4/4 = 1
The gradient of C = -2/5
The gradient of D = 2/6 = 1/3
The gradient of E = 3/4
The segment with the greatest gradient is F
b) The steepest segment has the higher gradient
From their calculated we have;
The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3
Therefore, we have;
B, E, D.
Answer:
Step-by-step explanation:
I do not know if this is completely correct
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