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tatiyna
3 years ago
13

WHAT IS 144/200 IN DECIMAL AND PERCENTAGE

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

Answer:

The answer is 0.73 & 73%

Step-by-step explanation:

miskamm [114]3 years ago
6 0

Answer:

.72 and 72% i believe

Step-by-step explanation:

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What is the smallest integer $n$ such that $5n + 3 > -10$?
Nataliya [291]

Answer:

-2

Step-by-step explanation:

5n+3= -10

5n = -13

n = -13/5

= -2.6

question is integer

so answer is -2

8 0
3 years ago
What is the value of (-3.8) +0 + (-1.6)+ 64?
Gemiola [76]

58.6

hope this helps (◍•ᴗ•◍)

6 0
3 years ago
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Alex buys 2 1/2 pounds of grapes. He buys 1 1/4 times as many pounds of apples as grapes. How many pounds of apples does he buy?
rusak2 [61]
So if, <span>2 1/2 = 5/2 and 1 1/4 = 5/4,
then </span>5/2 * 5/4 = 5*5 / 2*4 <span>= 25/8 is simplified to 3 1/8 pounds.</span>
4 0
3 years ago
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Please help me with this question
Elden [556K]

Answer:

Step-by-step explanation:

(a). SR = 15√2 km ≈ 21.2 km

R is 21.2 km due South-East of S

(b). RQ² = 35² + 15² ⇒ RQ = 5√14 km ≈ 38.1 km

R is 38.1 km due South-West of Q

4 0
3 years ago
Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom
IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0
3 years ago
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