3 years ago

The trapezoid shown is divided into a right triangle and a rectangle.

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

7 0

Where is the picture and question?

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

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as expected.

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The trapezoid shown is divided into a right triangle and a rectangle. ​

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