Answer:
for the first one its right 2 down 5
for the second one its right 5 down 2
for the third one its left 2 up 5
i hope this helps pls tell me if im wrong
Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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Don’t click on the link please
-6/5 is the slope. you start at point (0,0) and then move down 6 units and to the right 5 units and then create one point. from that point, go down 6 units and to the right 5 units and repeat. when you reach the bottom of the graph stop. go back to (0,0) and then move up 6 units and to the left 5 units. connect the points with a ruler and add arrows to each side. label your line with "y=-6/5x" on the line
