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uysha [10]
2 years ago
10

A line contains the points (10,7) and (5,-8). Write the equation of the line.

Mathematics
1 answer:
kobusy [5.1K]2 years ago
3 0
Y=3x-23
.
Hope this helps :)
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Ray has 3 boxes of chocolates. Each box has 4 layers of chocolates. Each layer has 4 rows of 4 chocolates each. He distributes a
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I believe it is (3*4*4*4)/16=12
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The product of two consecutive positive integers is 29 more than their sum. Find the integers
Rina8888 [55]
The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5    then: (x+1)=-5+1=-4  This is not the solution.
x₂=(1+11)/2=6    then: (x+1)=6+1=7    This solution is right.

Answer: the numbers would be 6 and 7. 
7 0
3 years ago
Marley had $495.66 in her bank account after she paid her monthly bills. She took her sister out to lunch, and paid $38.90. How
SOVA2 [1]

Answer: the answer is $456.76

Step-by-step explanation: All you have to do is subtract 38.90 from 495.66 and get your answer

5 0
2 years ago
All the info is in the pictures
Hunter-Best [27]
Bearing in mind that an absolute value expression is in effect a piece-wise function with two cases, thus

\bf |-n|=
\begin{cases}
+(-n)\\
-(-n)
\end{cases}\implies 
\begin{cases}
-n\\
n
\end{cases}
\\\\\\
n|-n|=2n\implies 
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n-n=2n\implies 0=2n\implies &0=n\\
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6 0
3 years ago
Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.
borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 14, p = 0.8

P(x>10)

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501

P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501

P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539

P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981

So P(x > 10) = 0.6981.

8 0
3 years ago
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