Newton's cooling model is ΔT = ΔTo * e ^ (-k t)
ΔTo = 200°F - 70°F = 130°F
k = 0.6
t = 2 hours
=> ΔT = 130 * e ^ (-0.6 t) = 130 * e^ (-0.6 * 2) = 130 * e ^ (-1.2)
ΔT = 39.15°F
ΔT = T - Tenvironment => T = ΔT + Tenvironment = 39.15°F + 70°F = 109.15°F ≈ 109 °F.
Answer: T = 109 °F
Answer:
<h2>In the attachment</h2>
Step-by-step explanation:

Switch a and f and see if that works
The equivalent expression of -14 - 6 is -14 - (+6)
<h3>What are
equivalent expression?</h3>
Equivalent expressions are expressions that have the same value when evaluated
<h3>How to determine the equivalent expression?</h3>
The expression is given as:
-14 - 6
Put the terms of the expression in brackets
-14 - (6)
Rewrite 6 as +6
-14 - (+6)
Hence, the equivalent expression of -14 - 6 is -14 - (+6)
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I hope this helps you
sec Q=1/cos Q
2=1/cos Q
cos Q= 1/2
Q=30+2.pi.n
Q=330+2.pi.n
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