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Feliz [49]
3 years ago
8

Find the nth term:

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

Answer:

n+3

Step-by-step explanation:

the relationship between those numbers are consistently adding 3 thus n +3

statuscvo [17]3 years ago
5 0

Answer:

3n-2

Step-by-step explanation:

An= A1+(n-1)d

d=3

An= 1+(n-1)3

An= 1+3n-3

An= 3n-2

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Help me solve this pleaseee
Drupady [299]
Since they are equal to 90 degrees. (complimentary angles)

6x-11+7x+10= 90

Combine like terms.

13x-1= 90

Add one to both sides.

13x= 91

x= 7

Plug that into the b.

7(7)+10

49+10

59


I hope this helps!
~kaikers
3 0
4 years ago
Example 2: Combining Use of the Multiplication and Addition Rules
bulgar [2K]

Answer:

The probability of getting 6's on both cubes is \frac{1}{36}.

The probability that the total score is at least 11 is \frac{1}{12}.

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is \frac{1}{6}

Probability of getting 6 on blue cube is \frac{1}{6}

Thus, the probability of getting 6's on both cubes is:

P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}

Hence, the probability of getting 6's on both cubes is \frac{1}{36}.

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}

Hence, the probability that the total score is at least 11 is \frac{1}{12}.

3 0
3 years ago
Which number is the additive inverse of -4<br> -442<br> O<br> -4<br> O<br> 45<br> V
frozen [14]

Answer:

it's the last one i mean 4&1/4

3 0
3 years ago
Read 2 more answers
Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
On a map to cities are about 50 mm apart if the scale is 1 cm equals 15.5 miles how far apart are the two cities
Mademuasel [1]

Given:

On a map to cities are about 50 mm apart.

Scale is 1 cm equals 15.5 miles.

To find:

The distance between two cities.

Step-by-step explanation:

We have,

1 cm = 15.5 miles

It means

10 mm = 15.5 miles             [1 cm = 10 mm]

Now,

10 mm on a map = 15.5 miles

1 mm on a map = \dfrac{15.5}{10} miles

                          = 1.55 miles

50 mm on a map = 50 × 1.55 miles

                            = 77.5

Therefore, the two cities are 77.5 miles apart.

4 0
3 years ago
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