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sammy [17]
3 years ago
7

Please help worth lot of points

Mathematics
2 answers:
Nat2105 [25]3 years ago
5 0
It could be y=1 possibly
vodka [1.7K]3 years ago
4 0

Answer:

y=1

Step-by-step explanation:

The numbers are all even, so if you are looking for what is in the middle of 2 lines then you would use a odd number.

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What is the due date of a 190-day loan made on March 12?
sasho [114]

Answer:

September 18 is the due date

Step-by-step explanation:

the rest of March = 19 days

April has 30

may has 31

june has 30

july has 31

and August has 31 also

...if we add all of those days it equals to 172 days....u need approximately 18 more days to make the 190 days (due date) ;take 18 days out of September ....making the due date the 18th of September

6 0
4 years ago
Please help due in 2 minutes
faltersainse [42]

Answer:

it is between 5 and 6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

  • 8 ≠ 16
<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

  • 169 = 169
<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

  • 34 ≠ 36
<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

\sf \: 25 + 16 = 49

  • 41 ≠ 49
<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

3 0
3 years ago
What is the tenth term in the sequence 5,8,11,14...? A. 29 B.32 C. 35 D. 38
Andrej [43]
Cause 5+3+8, 8+3=11 11+3=14, so 14+3=17 17+3=20, 20+3=23 23+3=26 26+3=29 29+3=32
so its 5, 8, 11, 14, 17, 20, 23, 26, 29, 32
so the answer is 32
3 0
3 years ago
Read 2 more answers
PLEASE ANSWER FAST
neonofarm [45]

Answer:

A. 2.25 and 0.5

B. 1 tomato

6 0
3 years ago
Read 2 more answers
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