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3 years ago

Please help my solve this problem. :(

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

The answer would be 90

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The function f(x) = 6x + 8 is transformed to function g through a horizontal stretch by a factor of 5. What is the equation of f

elixir [45]

Answer:

$g(x) = 30\cdot x +40$ ; $a \approx 1.898$ , $k = 40$ .

Step-by-step explanation:

The resultant function is obtained by multiplying $f(x)$ by a real number $k$ . That is:

$g(x) = k \cdot f (x)$

If $k = 5$ and $f(x) = 6\cdot x + 8$ , then $g(x)$ is:

$g(x) = 5\cdot (6\cdot x + 8)$

$g(x) = 30\cdot x +40$

Given that presence of the expression $g(x) = 6^{a}\cdot x + k$ , then:

$6^{a} = 30$ and $k = 40$

The value of a is obtained by applying the definition of logarithms:

$a = \log_{6}30$

$a \approx 1.898$

Finally, the value of k is found by direct comparison:

$k = 40$

6 0

3 years ago

I need your help because I don’t understand

kogti [31]

Alright, so first divide 20 km by 1.2 cm

16.6666666667

Multiply 16.6666666667 by 9

150

So it's 150 km!

Hope this helps!

5 0

3 years ago

Read 2 more answers

Can someone please help ASAP will give brainliest

qaws [65]

Answer:

This is an impossible question but my guess is:

Its probably a typo.

Because There is no possible way to answer this problem

5 0

4 years ago

The question is "the polynomial is even & positive, does it have 3 or 4 zeros?

sergejj [24]

Even function is symmetrical about the y axis
not sure what it means if the polynomial is positive

the zeroes are how many times it hits the x axis
it hits 4 times so 4 zeros

4 0

3 years ago

Read 2 more answers

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

5 0

3 years ago