Answer: We reject the null hypothesis, and we use Normal distribution for the test.
Step-by-step explanation:
Since we have given that
We claim that
Null hypothesis : 
Alternate hypothesis : 
There is 5% level of significance.
So, the test statistic would be
Since alternate hypothesis is left tailed test.
So, p-value = P(z≤-2.31)=0.0401
And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.
So, we reject the null hypothesis, and we use Normal distribution for the test.
99 and 59
X=big number
X-40 = small
X+ x-40 =158
2X -40=158
2X =198
X=99. Big number is 99
99-40 =59
99+59=158
Answer:
Step-by-step explanation:
55%
Answer: YES
Step-by-step explanation:
We need to write out the expressions
P= {m}
Q= {n}
R= {m+n}
If 2m=n then we can say;
P= {½n} Q= {n} & R= {³/²n}
It is obvious that the smaller number in Q is greater than the largest number in P
We can make some assumptions.
Let n= (x,y,z)
Consequently,
P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}
Therefore the median will be the middle element,
Median of P= ½y
Median of Q = y
Median of R = 1.5y
And 1.5y>1.5y
Then we can agree that the median of R is greater than the median of both P and Q
