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zhannawk [14.2K]
3 years ago
13

Could someone help with this please

Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

<em>x\</em><em>y</em><em>=</em><em>5</em><em>\</em><em>3</em><em>.</em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>[</em><em>I]</em>

<em>X=</em><em>5</em><em>y</em><em>\</em><em>3</em>

<em>X+</em><em>y</em><em>=</em><em>5</em><em>6</em>

<em>X=</em><em>5</em><em>6</em><em>-</em><em>y</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>[</em><em>ii</em><em>]</em>

<em>substitute</em><em> [</em><em>I]</em><em> </em><em>&</em><em>[</em><em>ii]</em>

<em>5</em><em>y</em><em>\</em><em>3</em><em>=</em><em>5</em><em>6</em><em>-</em><em>y</em>

<em>5</em><em>y</em><em>=</em><em>3</em><em>[</em><em>5</em><em>6</em><em>-</em><em>y</em><em>]</em>

<em>5</em><em>y</em><em>=</em><em>1</em><em>6</em><em>8</em><em>-</em><em>3</em><em>y</em>

<em>5</em><em>y</em><em>-</em><em>3</em><em>y</em><em>=</em><em>1</em><em>6</em><em>8</em>

<em>2</em><em>y</em><em>=</em><em>1</em><em>6</em><em>8</em>

<em>y=</em><em>1</em><em>6</em><em>8</em><em>\</em><em>2</em>

<em>y=</em><em>8</em><em>4</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>[</em><em>iii</em><em>]</em>

<em>substitute</em><em> </em><em>[</em><em>iii</em><em>]</em><em> </em><em>in </em><em>[</em><em>ii]</em>

<em>X=</em><em>5</em><em>6</em><em>-</em><em>8</em><em>4</em>

<em>X=</em><em>-</em><em>2</em><em>8</em>

<em>x-y=</em><em>-</em><em>2</em><em>8</em><em>-</em><em>8</em><em>4</em>

<em>=</em><em>-</em><em>1</em><em>1</em><em>2</em>

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