Question

PLEASEEE HELP ME FO THISSS​

Answer 1

As C is the mid-point of BD.

Therefore, BC=DC ...(i)

As AB ⊥ BD and ED ⊥ BD

So, ∠ABC= 90° and ∠EDC= 90°

Therefore, ∠ABC=∠EDC= 90° ...(ii)

As two line segments, AE and BD intersect at point C, so the vertically opposite angles are equal.

Therefore, ∠BCA=∠DCE ...(iii)

Now, in ΔABC and ΔEDC,

Angle, ∠BCA=∠DCE [ from equation (iii)]

Side, BC=DC [ from equation (i)]

Angle, ∠ABC=∠EDC [ from equation (ii)]

So, by ASA property of congruency, ΔABC and ΔEDC are congruent

Hence, ΔABC ≅ ΔEDC.