Maya’s school held an aluminum collection program in which they collected aluminum and brought it to be recycled. In the first w
2 answers:
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First, find the scale factor by dividing the first building's real-life height by its model height.
Now, we'll write an equation to find the model height of the second building.
Here is an equation where represents the real-life height of a building,
represents the scale factor, and
represents the model height of the same building.
Fill in the information we already know.
Divide both sides by .
So, the model height of the second building is inches.
Answer:
Given:
Mean, u = 135
Sample size, n = 42
Sample mean, x' = 126
Standard deviation = 16
Significance level = 0.05
1) The null and alternative hypotheses:
H0 : u = 135 (the revenue per day is $135)
H1 : u < 135 (the revenue per day is less than $135)
2) In this case, we have a left tailed test.
Let's use the formula:
t = - 3.645
Critical value: at a significance level of 0.05, left tailed test,
tcritical = -1.683
We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.
3) Given, a = 0.05, df = 41, left tailed test,
t-value = 2.02
For the corresponding confidence interval, we have:
CI = (121.014, 130.986)
4) Conclusion:
We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.