Question

The propeller of a World War II fighter plane is 2.30 m in diameter and spins at 1200 rev/min What is the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac

Answer 1

Answer:

v = 144.51 m/s

Explanation:

Given,

Diameter of Propeller, d = 2.30 m

               r = 2.30/2 = 1.15 m

Revolution spin, ω = 1200 rev/min

linear velocity, v = ?

$\omega = \dfrac{2\pi}{60}\times 1200$

$\omega =125.66\ rad/s$

using linear velocity formula

v = r ω

v = 1.15 x 125.66

v = 144.51 m/s

Hence, the linear speed of the tip is equal to 144.51 m/s.