Answer:
(a) (x-2)^2 +(y-2)^2 = 16
(b) r = 2
Step-by-step explanation:
(a) When the circle is offset from the origin, the equation for the radius gets messy. In general, it will be the root of a quadratic equation in sine and cosine, not easily simplified. The Cartesian equation is easier to write.
Circle centered at (h, k) with radius r:
(x -h)^2 +(y -k)^2 = r^2
The given circle is ...
(x -2)^2 +(y -2)^2 = 16
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(b) When the circle is centered at the origin, the radius is a constant. The desired circle is most easily written in polar coordinates:
r = 2
132 degrees
You’d do 180 - 48 as it’s the smallest angle and all triangle angles are 180 degrees
<span>686.924 to the nearest ten is 690.0 because the ones place is a number of 5 and above, which means you must move the tens place up 1 value.</span>
(g-h)(x) = 2x+1 -(<span>x-2)
</span>(g-h)(x) = 2x+1 - x + 2
(g-h)(x) = x + 3
Tan = opp/adj
Tan A = 16/12
