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insens350 [35]
3 years ago
6

The Hamilton Brush Company issued 2,500 shares of common stock worth $100,000.00 total. What is the par value of each share?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0
What we know here is that all 2500 shares together are worth 100 000 dollars in total. (it's 100 000.00 actually, but we can ignore the part after the point, as it's equal to 0).

This means that each of the shares is valid the whole sum divided by the number of shares, that is:
\frac{100000}{2500} = \frac{1000}{25} =40
(first i divided both denominator and numerator by 100)
So each value is worth 40 dolars.
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Members of the cooking club would like to learn how to make peach ice cream. There are 14 people in the club. Each member will n
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Answer:

Step-by-step explanation:

Total members = 14

Each member:

Peaches = 3

Pint of cream = 1

Cost

Peaches = x cent

Pint of cream = 46 cent

46 cent = $0.46

Cost per member = 3(x cent) + 0.46

= 3x cent + 0.46

Total cost for all members = 14(3x cent + 0.46)

= 42x cent + 6.44

8 0
3 years ago
One hour after yolanda started walking from x to y, a distance of 45 miles, bob started walking along the same road from y to x.
Rufina [12.5K]
<span>Answer: When bob starts walking The distance between them is 45-3 = 42 miles If they meet at time t then Yolanda would have walked X/3 minutes and Bob would have walked (42-X)/4 mins X/3 = (42-X)/4 so X = 18 Bob would have walked 42-18 = 24 miles.</span>
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3 years ago
Richelle drew hexagon KLMNOP. She thinks that the angles are congruent. How can she show that the angles are congruent without u
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Richelle can fold a hexagon in half and if they match up they will be congruent.
all angles would be congruent
6 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago
2) How many widgets (to the nearest tenth) can be produced by 360 workers in 20 hours?
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Answer:

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Step-by-step explanation:

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