Given that Bill
is on the school archery team. the target has a center bull's-eye and
two rings around the bull's-eye.
Given the table below that gives the probabilities of outcomes.
The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>
Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
Answer:
answer 3:
They are proportion so just put equal sign and see if hey make sense.
Or you can realize that longer side of tringle for the 2 trangles are 10 and 5 and shorter side of triangle are 5 and 2.5 respectively
Answer:
The length of AC = 4 and the length of A'C' = 1 so the scale factor is 1/4.
Answer:
∠3 = 60°
Step-by-step explanation:
Since g and h are parallel lines then
∠1 and ∠2 are same side interior angles and are supplementary, hence
4x + 36 +3x - 3 = 180
7x + 33 = 180 ( subtract 33 from both sides )
7x = 147 ( divide both sides by 7 )
x = 21
Thus ∠2 = (3 × 21) - 3 = 63 - 3 = 60°
∠ 2 and ∠3 are alternate angles and congruent, hence
∠3 = 60°
Answer:
99 points
Step-by-step explanation:
Average of a data a is the sum of the data divided by the number of data.
Average = sum of data ÷ number of data
A = T/n .....1
For the average of 5 test to be 90.
The total sum of score must be;
Number of tests n = 5
Average A = 90
Substituting into equation 1
90 = T/5
T = 90×5 = 450 points
The total score must be equal to 450 point to have an average of 90 points
The sum of the first four test is;
88+84+88+91 = 351
Let x represent the first score,
351 + x = 450
x = 450 - 351
x = 99 points
The minimum score she can get in the fifth test is 99 points
