47.12
I did this last year :))
Answer: B
Because they’re congruent angles
Answer:
The first question answer is Fred. The second one is 1/7. Sorry that is all i know.
Step-by-step explanation:
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,
![(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%28x%5E2-y%5E2%29%5E2%2B%282xy%29%5E2)
Since, given the difference of the squares of the numbers is 5 that is ![(x^2-y^2)^2=5](https://tex.z-dn.net/?f=%28x%5E2-y%5E2%29%5E2%3D5)
And the product of the numbers is 6 that is ![xy=6](https://tex.z-dn.net/?f=xy%3D6)
Using identity, we have,
![(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%28x%5E2-y%5E2%29%5E2%2B%282xy%29%5E2)
Substitute, we have,
![(x^2+y^2)^2=(5)^2+(2(6))^2](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%285%29%5E2%2B%282%286%29%29%5E2)
Simplify, we have,
![(x^2+y^2)^2=25+144](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D25%2B144)
![(x^2+y^2)^2=169](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D169)
Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
Ist amount paid = $1500
Making $350 for 10 months = 10*350 = $3500
Total amount paid = 1500 + 3500 = 5000
So an amount of $5000 was paid to cover the cost of $4500 within the ten month period.
I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT) R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 % per annum.