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Olenka [21]
3 years ago
8

A scientist uses 20 grams of carbon every 10 minutes during an experiment. If the experiment lasted 2 hours, how many total kilo

grams of carbon did they use?
Mathematics
2 answers:
viva [34]3 years ago
6 0
240 grams or 0.24 kilograms I think
ruslelena [56]3 years ago
4 0

Answer:

240 grams

Step-by-step explanation:

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5. (9) Letf- ((-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)) and let g- ((-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)j. Find: a. (g f (0
pashok25 [27]

Answer:  g(f(0)) = 2 and  (f ° g)(2) = -3.

Step-by-step explanation:  We are given the following two functions in the form of ordered pairs :

f = {(-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)}

g = {(-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)} .

We are to find g(f(0))  and   (f ° g)(2).

We know that, for any two functions p(x) and q(x), the composition of functions is defined as

(p\circ q)(x)=p(q(x)).

From the given information, we note that

f(0) = 0,  g(0) = 2,  g(2) = 2  and  f(2) = -3.

So, we get

g(f(0))=g(0)=2,\\\\(f\circ g)(2)=f(g(2))=f(2)=-3.

Thus,  g(f(0)) = 2 and  (f ° g)(2) = -3.

8 0
3 years ago
Find the first partial derivatives of the function. (sn = x1 + 2x2 + ... + nxn; i = 1, ..., n. give your answer only in terms of
liq [111]

Answer:

  ∂u/∂xi = i·cos(sn)

Step-by-step explanation:

For u = sin(v), the partial derivative of u with respect to xi is ...

  ∂u/∂xi = cos(v)·∂v/xi

In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...

  ∂u/∂xi = i·cos(sn)

6 0
3 years ago
(03.04 LC) When the function f(x) = 4(2)x is changed to f(x) = 4(2)x − 13, what is the effect? There is no change to the graph b
Ksenya-84 [330]

Answer:

The y-intercept moves 13 spaces lower

Step-by-step explanation:

3 0
3 years ago
Factor this completely
bezimeni [28]

28n^4 +16n^3 -80n^2  

we can factor out a 4n^2

4n^2 (7n^2 +4n - 20)

4n^2 (7n-10) (n+2)

4 0
3 years ago
Solve each given equation and show your work. Tell whether it has one solution, an infinite number of solutions, or no solutions
Natali [406]
I hope this helps you

4 0
3 years ago
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