5 . 3n<br><br>
A. 15,30,45,60<br>
B.5,15,45,135<br>
C.0,15,45,135<br>
D.15,45,135,405
TiliK225 [7]
Answer:
3n
Step-by-step explanation:
Answer:
Height of tree is
<em>15 m.</em>
<em></em>
Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled 

Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22
<em>15 m</em>
Answer:
(-3, 2)
Step-by-step explanation:
{3x=7y=5
{5x-2y=-19
solve....
maybe it was 3x + 7y = 5
and 5x - 2y = -19
2*(3x + 7y = 5)
7*(5x - 2y = -19)
-------------
6x + 14y = 10
35x -14y = -133
41x = -123
x = -3
y = ...
5*(-3) - 2y = -19
-15 - 2y = -19
2y = 4
y = 2
(-3, 2)
Answer:
Step-by-step explanation:
Answer:
scalene acute
Step-by-step explanation: