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FromTheMoon [43]
3 years ago
13

HELP ME I REALLY NEED THIS!!!

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0

2+1× y =? Y=the number of weeks

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Answer this math question
aalyn [17]

Answer:

Angle D is complementary to angle A

Step-by-step explanation:

Complementary angles sum to 90 degrees.

Since angle is B is 90 degrees, the sum of angles A and D are also 90 degrees to make a straight line with an angle measure of 180 degrees.

3 0
2 years ago
There were 128 newspapers. Every 8newspapers were bundled together . How many bundles were there ?
Katarina [22]

divide

128 \div 8

5 0
3 years ago
Solve. k + 6 > 19
Readme [11.4K]

Answer:

k > 13

Step-by-step explanation:

k+6 > 19\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:k > 13\:\\ \:\mathrm{Interval\:Notation:}&\:\left(13,\:\infty \:\right)\end{bmatrix}

\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}

k+6-6 > 19-6

\mathrm{Simplify}

k > 13

Thus, the answer is k > 13

[RevyBreeze]

8 0
2 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
Five and twenty nine hundredths
maks197457 [2]
5.029 is five and twenty nine hundredths in decimal form.
7 0
3 years ago
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