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3 years ago

HELP ME I REALLY NEED THIS!!!

Mathematics

1 answer:

marysya [2.9K]3 years ago

7 0

2+1× y =? Y=the number of weeks

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Answer this math question

aalyn [17]

Answer:

Angle D is complementary to angle A

Step-by-step explanation:

Complementary angles sum to 90 degrees.

Since angle is B is 90 degrees, the sum of angles A and D are also 90 degrees to make a straight line with an angle measure of 180 degrees.

3 0

2 years ago

There were 128 newspapers. Every 8newspapers were bundled together . How many bundles were there ?

Katarina [22]

divide

$128 \div 8$

5 0

3 years ago

Solve. k + 6 > 19

Readme [11.4K]

Answer:

k > 13

Step-by-step explanation:

$k+6 > 19\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:k > 13\:\\ \:\mathrm{Interval\:Notation:}&\:\left(13,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}$

$k+6-6 > 19-6$

$\mathrm{Simplify}$

$k > 13$

Thus, the answer is k > 13

[RevyBreeze]

8 0

2 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

Five and twenty nine hundredths

maks197457 [2]

5.029 is five and twenty nine hundredths in decimal form.

7 0

3 years ago