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vampirchik [111]
2 years ago
11

Which is a simplified form of the expression 5c – 7(2c – 4)?

Mathematics
1 answer:
Sonja [21]2 years ago
5 0
1.
5c-7(2c-4)
5c-14c+28
-9c+ 28
2.
3(m+1) + 2m
3m+3+2m
5m+3
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If the bakers percentage for raisins in a raisin bread formula is 8% and the bakers percentage for flour is 100%, what amount of
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How many pounds were the 8% formula?
4 0
3 years ago
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Which of the following is the interest on $6000 at 6% compounded semiannually for eight years?
ryzh [129]

Answer:

$3628.24

Step-by-step explanation:

we use the formula for accrued value (A) with compounded interest:

A=P(1+\frac{r}{n})^{n*t}

where A= accrued value (principal plus the accumulated  interest)

P = principal -> in our case $6000

r = annual interest rate (in decimal form) -> in our case 0.06

n = number of compoundings per year. In our case 2 (semiannually)

t = time in years -> in our case 8

A=P(1+\frac{r}{n})^{n*t}\\A = 6000(1+\frac{0.06}{2})^{16}\\ A= 6000(1+0.03)^{16}\\A = $9628.24

Since this is the value of principal plus accumulated interest, we subtract from it the principal ($6000) to get the value of just the interest:

$9628.24 - $6000 = $3628.24

4 0
2 years ago
Point G is on line segment{FH}
Angelina_Jolie [31]

Answer:

FG = 7

Step-by-step explanation:

5x+2+3x-1=9

8x+1=9

8x = 8

x = 1

FG = 5(1)+2 = 7

8 0
3 years ago
Select all irrational numbers.
const2013 [10]
The answers are A and D.
The numbers that you cannot simplify without having a radical in the answer are irrational numbers. 

√(4/16) = 1/4 or -1/4, rational number
√(9/16) = 3/4 or -3/4, rational number
√(9/4) = 3/2 or -3/2, rational number

√(3/16) = √(3)/4, NOT a rational number, cannot remove radical
√(3/4) = √(3)/2, NOT a rational number, cannot remove radical 
5 0
3 years ago
Read 2 more answers
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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