$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$

3 0

3 years ago

Marla bought 7 boxes. A week later, half of all her boxes were destroyed in a fire. There are now only 22 boxes left. How many d

Alchen [17]

She should have started with 44 boxes

3 0

3 years ago

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Evaluate the expression when a=1\4 and b=6. -8ab

tester [92]

Answer:

-12

Step-by-step explanation:

-8 * ( 1/4) * (6)

= -12

4 0

2 years ago

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12x-39<9 and -4x+3<-6

gulaghasi [49]

Remember, you can do anything to an equation as long as you do it to both sides

and when multiply or divide by a negative in inequalities, flip the direction of the sign

12x-39<9
add 39 to both sides
12x<48
divde bothh sides by 12
x<4

-4x+3<-6
minus 3 both sides
-4x<-9
times both sides by -1 and flip sign
4x>9
divide both sides by 4
x>9/4

4 0

3 years ago

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