Ask question

Ask question

All categories

Lubov Fominskaja [6]

3 years ago

6

15 FIFTEEN POINTS AND BRAINLIEST!!

2 answers:

Gnesinka [82]3 years ago

8 0

Answer:

I believe its B

Step-by-step explanation:

enot [183]3 years ago

3 0

Answer:

The second one

Step-by-step explanation:

You might be interested in

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.

Gala2k [10]

Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2

5 0

3 years ago

The equation is equivalent to u = rst. <br><br> True/ False

Jlenok [28]

The equation r = u/st is equivalent to u = rst .

True

7 0

3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

3 years ago

-17=x-15<br> I'm stuck so can someone help

Strike441 [17]

Answer:

-2

Step-by-step explanation:

-2-15

-2 +(-15)

-17

8 0

3 years ago

Read 2 more answers

HELP PLEASE IM STUCK

andre [41]

Answer:

360-(124+124)= 360-248=122 divided by 4=30.5

6 0

4 years ago