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saul85 [17]
3 years ago
11

Help? I don’t understand this math

Mathematics
2 answers:
Wittaler [7]3 years ago
4 0

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>J</u></em><em><u>:</u></em></h2>

<em><u>{x}^{3}  {y}^{3}</u></em>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

Width of the rectangular prism

= x

Length of the rectangular prism

=  {x}^{2} y

Height of the rectangular prism

=  {y}^{2}

<em><u>Therefore</u></em><em><u>, </u></em>

Volume of the rectangular prism

= <em>Width</em><em> </em><em>×</em><em> </em><em>Length</em><em> </em><em>×</em><em> </em><em>Height</em><em> </em>

= x \times  {x}^{2} y \times  {y}^{2}

=  {x}^{3}  {y}^{3}

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>The</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>volume</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>prism</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em>

<em><u>Option</u></em><em><u> </u></em><em><u>J</u></em><em><u>:</u></em>

{x}^{3}  {y}^{3}

nexus9112 [7]3 years ago
4 0
The answer should be A
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On the same day, Parker’s friend, Peggy, was charged $5 for 1 1/2 lb. of gummy candy. Explain in terms of the graph why this mus
Maksim231197 [3]

Answer:

After a quick online search, I've found that the complete question is:

a) Parker paid $4.50 for three pounds of gummy candy. Assuming each pound of gummy candy costs  the same amount, complete the table of values representing the cost of gummy candy in pounds.

Then we want to graph the points, and then comes our question:

c) On the same day, Parker’s friend, Peggy, was charged $5 for 1 1/2 lb. of gummy candy. Explain in terms of the graph why this must be a mistake.

So first, we know that this is a proportional relationship (each pound of candy costs the same)

And 0 pounds of candy should cost $0.

Then the relation between y (price) and x (number of lb) is:

y = k*lb

where k is the cost per lb.

Knowing that Parker paid $4.50 for three pounds of gummy candy, the relation is:

$4.50 = k*3lb

($4.50/3lb) = k = $1.50/lb

Then the linear relation is:

y = ($1.50/lb)*x

Now, in this question we can see that Parker's friend was charged $5 for ( 1 and 1/2) lb of candy.

If we replace those values in the equation, we get:

$5 = ($1.50/lb)*(1 + 1/2)lb = $2.25

This equation is false, then, in terms of the graph, the point ( (1 and 1/2)lb, $5) does not belong on the graph that you found in the previous points.

6 0
3 years ago
Will someone please answer this ASAP?
Irina-Kira [14]
Volume of cone = pi*r^2*h/3
given r=10 cm, h=4 cm,
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5 0
3 years ago
Still confusing to me!!!!
juin [17]

Answer:

  (a)  2(x -a)

  (b)  4x +2h

Step-by-step explanation:

Fill in the function arguments and simplify.

a.

\dfrac{f(x)-f(a)}{x-a}=\dfrac{(2x^2-7)-(2a^2-7)}{x-a}\\\\=\dfrac{2x^2-7-2a^2+7}{x-a}=\dfrac{2(x^2-a^2)}{x-a}\\\\=\dfrac{2(x-a)(x+a)}{(x-a)}=2(x+a)

__

b.

\dfrac{f(x+h)-f(x)}{h}=\dfrac{(2(x+h)^2-7)-(2x^2-7)}{h}\\\\=\dfrac{2x^2+4xh+2h^2-7-2x^2+7}{h}=\dfrac{4xh+2h^2}{h}\\\\=4x+2h

8 0
3 years ago
Given the following formula, solve for t v= u + at
Dafna1 [17]

Answer:

rc

Step-by-step explanation:

rc

7 0
3 years ago
Read 2 more answers
How much has to be invested at 5.1% interst compound continuously to have 17,000 after 14 years
Montano1993 [528]

I do not know exactly, but it seems to be correct                                                                             A = Pe^(r*t)  Compounding continously

17,000 = Пэ^(.051*14)

17,000/e^(.714) = P

$8324.59  = P    


7 0
3 years ago
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