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3 years ago

What’s the answer no work needed Given f (x) = 5x2 and g(x) = 2x + 3, find f(g(-4))

Mathematics

1 answer:

Crazy boy [7]3 years ago

4 0

Answer:

125

Step-by-step explanation:

Given

f(x) = 5x²

g(x) = 2x + 3

Now

g(-4) = 2 * (- 4) + 3

= - 8 + 3

= - 5

Also

f(g(-4)) = f( -5)

= 5 * ( -5)²

= 5 * 25

= 125

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Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume

Sphinxa [80]

Answer: (1.55, 6.45)

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline\ {x}\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Sample size : n=41

Sample mean : $\overline{x}=4.0\text{ kg}$

Standard deviation : $\sigma=6.1\text{ kg}$

Then, 99% confidence interval for population mean will be :_

$4\pm\ (2.576)\dfrac{6.1}{\sqrt{41}}\\\\\approx4\pm2.45\\\\=(4-2.45, 4+2.45)=(1.55, 6.45)$

8 0

4 years ago

Is 56 a multiple of 6?

lbvjy [14]

No, 56 is a multiple of 7 though.

8 0

3 years ago

Plzz help me find the answer

serious [3.7K]

It’s the first one 9/2.

5 0

3 years ago

Find y when x=77, if y varies inversly as x, and y = 23 when x = 115.

Eduardwww [97]

The required value of y is 2645 / 77 when x = 77.

Step-by-step explanation:

1. Let's check the information given to answer:

if y varies inversely as x, and y = 23 when x = 115. Find y when x=77

2. What is y when x = 77?

As the statement "y varies inversely as x" translates into y = k/x

If we let y = 23 and x = 115, the constant of variation becomes

23 = k ÷ 115

k = 23 × 115

k = 2645

Thus the specification equation is y = 2645 ÷ x . Now, letting x = 77, we obtain

y = 2645 ÷ x

y = 2645 ÷ 77

So, The required value of y = 2645 / 77 when x = 77

#learnwithBrainly

7 0

4 years ago

If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)

SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

$1V=1J/C$

and the energy units in terms of meters, seconds and kilograms are:

$1J= 1kg\frac{m^{2}}{s^{2}}$

So the unit of volt is

$1V= kg \frac{m^{2}}{Cs^{2}}$

So the velocity expression (it can not be read completly) but i guess that it could be as follows

$vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}$

So the unit analysis would be

$vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}$

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

$vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}$

Applying square root

$vf_{a} = \frac{m}{s}$

7 0

3 years ago